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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020
PhysicsEasysingle choice

The work function of the metalAis equal to the ionization energy of the hydrogen atom in the first excited state. The work function of the metalBis equal to the ionization energy ofHe+ ion in the second orbit. Photons of the same energyEare incident on bothAandB. The maximum kinetic energy of photoelectrons emitted fromAis twice that of photoelectrons emitted fromB. Value ofE( ineV) is

Options:

Answer:
A
Solution:

En=13.6Z2n2

WA= ionization energy of an electron in 2nd orbit of the hydrogen atom= 3.4 eV

WB= ionization energy of an electron in 2nd orbit of He+ion

= 13.6 eV.

Now, given that

KA=2KB

orE-WA=2E-WB

∴  E=2WB-WA=23.8 eV

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect
⏱ 2mℹ️ Source: PYQ_2020

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