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PhysicsModern PhysicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A nucleus with mass number $220$ initially at rest emits an $α$ -particle. If the $Q$ value of the reaction is $5.5 MeV$ , then calculate the kinetic energy of the $α$ -particle.

Options:

Answer:

Solution:

Given that $K_{1} + K_{2} = 5.5 MeV$ ... (i)

From conservation of linear momentum,

$p_{1} = p_{2}$

$\sqrt{2 K_{1} (216 m)} = \sqrt{2 K_{2} (4 m)}$ (As $p = \sqrt{2 K m}$ )

$K_{2} = 54 K_{1}$ ... (ii)

Solving Eqs. (i) and (ii), we get

$K_{2} =$ K.E. of $α$ -particle $5.4 MeV$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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