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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

If $13.6 eV$ energy is required to ionize the hydrogen atom, then the energy required to remove an electron from its first excited state is

Answer:

Solution:

The energy of an electron in hydrogen atom is

$E = - \frac{13.6}{n^{2}} eV$

So, the energy required to remove an electron from $n = 2$ state is

$|E| = \frac{13.6}{2^{2}} eV = \frac{13.6}{4} = 3.4 eV$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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