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PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

Light of two different frequencies whose photons have energies $1 eV$ and $2.5 eV$ respectively illuminate a metallic surface whose work function is $0.5 eV$ successively. The ratio of maximum speeds of both emitted electrons will be :

Options:

Answer:

Solution:

$K . E = ϕ - ϕ_{0}$

$K . E_{1} = 1 eV - 0.5 eV = 0.5 eV$

$K . E_{2} = 2.5 eV - 0.5 eV = 2 eV$

$\frac{K . E_{1}}{K . E_{2}} = \frac{0.5 eV}{2 eV} = \frac{1}{4}$

$\frac{v_{1}}{v_{2}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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