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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The energy required to ionise a hydrogen like ion in its ground state is $9$ Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited stale to the ground state?

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Answer:

Solution:

$\frac{h c}{λ} = (13 . 6 e V) z^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$
$n_{1} = 1$
$n_{2} = 3$
$\frac{h c}{λ} = (13.6 e V) (3^{2}) [\frac{1}{1^{2}} - \frac{1}{3^{2}}]$
$\Rightarrow \frac{h c}{λ} = (13.6 e V) (9) (\frac{8}{9})$
Wavelength $= \frac{1240}{8 \times 13.6} nm$
$λ = 11.39 nm$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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