Physics - Modern Physics Question with Solution | TestHub

$\text{The kinetic energy of electron (KE)}=\frac{{\text{KZe}}^2}{\text{2r}}$

$\text{Potential energy of electron (PE)}=\frac{-{\text{KZe}}^2}{\text{r}}\Rightarrow \text{PE}=-2\text{KE}$

In this calculation, the electric potential and potential energy are zero at infinity.

Total energy = PE + KE = - 2KE + KE = - KE

PE of electron in this first excited state

= - 2 KE = -2 (3.4) = - 6.8 eV