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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The electron in a hydrogen atom makes a transition from $n = n_{1}$ to $n = n_{2}$ state. The time period of the electron in the initial state $(n_{1})$ is eight times that in the final state $(n_{2})$ . The possible values of $n_{1}$ and $n_{2}$ are

Options:

Answer:

Solution:

In a hydrogen atom, the time period is given by

$T \propto n^{3}$

$\frac{T_{1}}{T_{2}} = {(\frac{n_{1}}{n_{2}})}^{3} \Rightarrow \frac{8}{1} = {(\frac{n_{1}}{n_{2}})}^{3}$

$\Rightarrow \frac{n_{1}}{n_{2}} = \frac{2}{1}$

Thus, $n_{1} = 4$ and $n_{2} = 2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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