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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2020

PhysicsEasysingle choice

The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen-like atom of atomic number $Z$ . The value of $Z$ is equal to

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Answer:

Solution:

$13 .6 (Z^{2}) (\frac{1}{2^{2}} - \frac{1}{\infty}) = 13 .6 (\frac{1}{1^{2}} - \frac{1}{\infty^{2}})$

$\Rightarrow Z = 2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2020

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