Start Free Mock LoginAlready registered? Login here

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsDe Broglie & Matter WavesHard2 minPYQ_2019

PhysicsHardsingle choice

An electron is accelerated through a potential difference of $10,000 V .$ Its de Broglie wavelength is (nearly): $(m_{e} = 9 \times 1 0^{- 31} k g)$ NEET 2019 (All India)

Options:

Answer:

Solution:

The energy of electron $K$ $= 10^{4} e V$
$λ = \frac{h}{m v} = \frac{h}{\sqrt{2 m K}} = \frac{6.63 \times 10^{- 34}}{\sqrt{2 \times 9.1 \times 10^{- 31} \times 10^{4} \times 1.6 \times 10^{- 19}}} ≅ 12.2 \times 10^{- 12} m$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2019

Doubts & Discussion

Loading discussions...