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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2018

PhysicsEasysingle choice

A deutron has an energy of $4 MeV$ when accelerated through a potential difference $V$ . What will be the energy of an $α$ -particle accelerated by source $V$ ?

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Answer:

Solution:

Energy of a charged particle when accelerated through V $E = q V So, \frac{E _{d}}{E _{α}} = \frac{q _{d}}{q _{α}} \times \frac{V _{d}}{V _{α}} = \frac{( e ) V}{( 2 e ) V} = \frac{1}{2} E_{α} = 2 E_{d} = 2 \times 4 MeV = 8 MeV$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2018

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