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PhysicsModern PhysicsPhotoelectric effectHard2 minPYQ_2016

PhysicsHardstatement

When photons of wavelength $λ_{1}$ are incident on an isolated sphere, the corresponding stopping potential is found to be $V$ . When photons of wavelength $λ_{2}$ are used, the corresponding stopping potential was thrice that of the above value. If light of wavelength $λ_{3}$ is used then find the stopping potential for this case:

Options:

Answer:

Solution:

$\frac{h c}{λ_{1}} = \frac{h c}{λ_{0}} + e V$ ...(i)

$\frac{h c}{λ_{2}} = \frac{h c}{λ_{0}} + 3 e V$ ...(ii)

$\frac{h c}{λ_{3}} = \frac{h c}{λ_{0}} + e V^{'}$ ....(iii)

Equation (i) and (ii)

$\frac{3}{2 λ_{1}} - \frac{1}{2 λ_{2}} = \frac{1}{λ_{0}}$

$\frac{h c}{λ_{3}} - h c [\frac{3}{2 λ_{1}} - \frac{1}{2 λ_{2}}] = e V^{'}$

$\frac{h c}{e} [\frac{1}{λ_{3}} - \frac{3}{2 λ_{1}} + \frac{1}{2 λ_{2}}] = V^{'}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2016

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