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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2016

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If an electron in a hydrogen atom jumps from the third orbit to the second orbit, it emits a photon of wavelength $λ$ . When it jumps from the fourth orbit to the third orbit, the corresponding wavelength of the photon will beNEET 2016 (Phase 2)

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Answer:

Solution:

$\frac{1}{λ} = R [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$\Rightarrow λ = \frac{1}{R (\frac{1}{2^{2}} - \frac{1}{3^{2}})}$

$\Rightarrow λ^{'} = \frac{1}{R (\frac{1}{3^{2}} - \frac{1}{4^{2}})}$

$\Rightarrow \frac{λ^{'}}{λ} = \frac{(\frac{1}{2^{2}} - \frac{1}{3^{2}})}{(\frac{1}{3^{2}} - \frac{1}{4^{2}})} \Rightarrow λ^{'} = \frac{20}{7} λ$ .

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2016

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