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PhysicsModern PhysicsDe Broglie & Matter WavesEasy2 minPYQ_2016

PhysicsEasysingle choice

An electron of mass m and a photon have same energy $E.$ The ratio of de-Broglie wavelengths associated with them is:
( $c$ being velocity of light)NEET 2016 (Phase 1)

Options:

Answer:

Solution:

De-Broglie wavelength is given by

$λ_{e} = \frac{h}{p} = \frac{h}{\sqrt{2 m . E}}$ for electron

De-Broglie wavelength of photon is given by

$λ_{p} = \frac{h}{p} = \frac{h}{\frac{E}{c}} = \frac{h c}{E}$

$\frac{λ_{e}}{λ_{p}} = \frac{1}{\sqrt{2 m E}} . \frac{E}{c} = \frac{1}{c} \sqrt{\frac{E}{2 m}}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2016

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