A nuclear transformation is given by Y ( n , α ) → 3 Li 7 . The nucleus of element Y is

Y ( n , α ) the nucleus splits into α -particle and neutrons i.e. Z Y A + 0 n 1 ⟶ 3 L i 7 + 2 He 4 So A + 1 = 7 + 4 ⇒ A = 10 and Z + 0 = 3 + 2 or Z = 5 Hence, the nucleus of element Y is boron 5 Y 10 = 5 B 10

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PhysicsModern PhysicsNuclear physicsMedium2 minPYQ_2015

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A nuclear transformation is given by $Y (n, α) \to_{3} Li^{7}$ . The nucleus of element $Y$ is

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$Y (n, α)$ the nucleus splits into $α$ -particle and neutrons i.e. $Z^{Y}^{A} +_{0} n^{1} ⟶_{3} L_{i}^{7} +_{2} He^{4}$ So $A + 1 = 7 + 4 \Rightarrow A = 10$ and $Z + 0 = 3 + 2$ or $Z = 5$ Hence, the nucleus of element $Y$ is boron $_{5} Y^{10} =_{5} B^{10}$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2015

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