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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2015

PhysicsMediumsingle choice

When the momentum of a photon is changed by an amount $p$ ' then the corresponding change in the de-Broglie wavelength is found to be $0.20%$ . Then, the original momentum of the photon was

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Solution:

As, we know de-Broglic wavelength, $λ = \frac{h}{p} ∴ λ \propto \frac{1}{p}$ $\Rightarrow \frac{Δ p}{p} = - \frac{Δ λ}{λ} ∴ \frac{Δ p}{p} = \frac{Δ λ}{λ}$ $\Rightarrow \frac{p ^{'}}{p} = \frac{0.20}{100} = \frac{1}{500}$ or, $p = 500 p^{'}$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2015

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