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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2015

PhysicsEasysingle choice

As an electron makes a transition from an excited state to the ground state of a hydrogen-like atom/ion

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Solution:

$U = - \frac{e^{2}}{4 {πε}_{0} r}$ , $U$ $=$ potential energy, $K = \frac{e^{2}}{4 {πε}_{0} r}$
$K$ =kinetic energy. $E = U + K = - \frac{e^{2}}{8 {πε}_{0} r}$ , $E$ =total energy $∴$ As electron de-excites from an excited state to ground state, $K$ increases, but $U$ and $E$ decrease.

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2015

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