A photon is incident having frequency 1 × 1 0 14 sec − 1 . Threshold frequency of metal is 5 × 1 0 13 sec − 1 . Find the kinetic energy of the ejected electron.

The relation between kinetic energy, threshold frequency and frequency of photon is given as 2 1 m v 2 = ( h v − h v 0 ) = h ( 1 × 1 0 14 − 5 × 1 0 13 ) k = h ( 5 × 1 0 13 ) = 6.67 × 1 0 − 34 × 5 × 1 0 13 = 3.3 × 1 0 − 20 J

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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectMedium2 minPYQ_2012

PhysicsMediumsingle choice

A photon is incident having frequency $1 \times 1 0^{14} sec^{- 1}$ . Threshold frequency of metal is $5 \times 1 0^{13} sec^{- 1}$ . Find the kinetic energy of the ejected electron.

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Answer:

Solution:

The relation between kinetic energy, threshold frequency and frequency of photon is given as $\frac{1}{2} m v^{2} = (h v - h v_{0})$ $= h (1 \times 1 0^{14} - 5 \times 1 0^{13})$ $k = h (5 \times 1 0^{13})$ $= 6.67 \times 1 0^{- 34} \times 5 \times 1 0^{13}$ $= 3.3 \times 1 0^{- 20} J$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2012

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