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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2011

PhysicsEasysingle choice

Energy required for the electron excitation in $Li^{++}$ from the first to the third Bohr orbit is :

Options:

Answer:

Solution:

$E_{n} = - 13.6 \frac{Z ^{2}}{n ^{2}}$ $E_{L}^{**} = - 13.6 \times \frac{9}{1} = - 122.4 eV$ $E_{L}^{**} = - 13.6 \times \frac{9}{9} = - 13.6 eV$ $Δ E = - 13.6 - (- 122.4)$ $= 108.8 eV$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2011

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