Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum speeds of emitted

Question

Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum speeds of emitted electrons will beNEET 2011 (Screening)

TestHub · Accepted Answer

Kinetic energy KE = ϕ − ϕ 0 ​ Here, KE 1 ​ = 1 − 0.5 = 0.5 eV ​ KE 2 ​ = 2.5 − 0.5 = 2 eV ∴ KE 2 ​ KE 1 ​ ​ = 2 0.5 ​ = 4 1 ​ or y 2 2 ​ y 1 2 ​ ​ = 4 1 ​ or y 2 ​ y 1 ​ ​ = 4 1 ​ ​ = 2 1 ​ ​

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