Physics - Modern Physics Question with Solution | TestHub

For photon, ${\lambda }_P=\frac{hc}{E}$ Here, $E$ is energy of photon. For proton, ${\lambda }_p=\frac{h}{\sqrt{2mK}}$ Here, $m$ and $K$ be mass and kinetic energy of proton respectively. $$\therefore \frac{{\lambda }_p}{{\lambda }_P}=\frac{E}{c}\sqrt{2mK}\propto E^{1/2}(\because E=K\text{ Given })$$