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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2010

PhysicsEasysingle choice

What would be the radius of second orbit of $He^{+}$ ion?

Answer:

Solution:

$r = \frac{n ^{2}}{Z} \times 0.529$ For $He^{+}, n = 2, Z = 1$ $r = \frac{4}{2} \times 0.529 = 1.058 \overset{˚}{A}$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2010

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