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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2009

PhysicsMediumsingle choice

If the kinetic energy of a particle is increased by 16 times, the percentage change in the de Broglie wavelength of the particle is

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Solution:

$λ = \frac{h}{m v} = \frac{h}{2 m E}$ or $λ \propto \frac{1}{E}$ $∴ \frac{λ ^{'}}{λ} = \frac{E}{E ^{'}} = \frac{1}{16} = \frac{1}{4}$ $%$ change in wavelength $= (\frac{λ - λ ^{'}}{λ}) \times 100$ $= (1 - \frac{λ ^{'}}{λ}) \times 100 = (1 - \frac{1}{4}) \times 100 = 75%$

Stream:AIIMSSubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2009

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