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PhysicsModern PhysicsNuclear physicsMedium2 minPYQ_2009

PhysicsMediumsingle choice

What is the particle $x$ in the following nuclear reaction : $_{4}^{9} Be +_{2}^{4} He \to_{6}^{12} C + x$

Answer:

Solution:

$_{4}^{9} Be +_{2}^{4} He \to_{6}^{12} C +_{0}^{1} X$ Hence X represents neutron $(_{0}^{1} n)$

Stream:WBJEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2009

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