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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2009

PhysicsMediumsingle choice

The radius of hydrogen a tomin its ground state is $5.3 \times 1 0^{- 11} m$ . After collision with an electron it is found to have a radius of $21.2 \times 1 0^{- 11} m$ . What is the prindpal quantum number $n$ of the final state of atom?

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Answer:

Solution:

$r \propto n^{2}$ ie, $\frac{r _{f}}{r _{i}} = (\frac{n _{f}}{n _{i}})^{2}$ $\Rightarrow \frac{21.2 \times 1 0 ^{- 11}}{5.3 \times 1 0 ^{- 11}} = [\frac{n}{1}]^{2} \Rightarrow n^{2} = 4 \Rightarrow n = 2$

Stream:MHT_CETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2009

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