Monochromatic light of frequency 6.0 × 1 0 14 Hz is produced by a laser. The power emitted is 2 × 1 0 − 3 W . The number of photons emitted, on the average, by the source per second is:NEET 2007

η = m v p = 6.62 × 1 0 − 34 × 6 × 1 0 14 2 × 1 0 − 3 = 5 × 1 0 15

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PhysicsModern PhysicsPhotoelectric effectMedium2 minPYQ_2007

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Monochromatic light of frequency $6.0 \times$ $1 0^{14} Hz$ is produced by a laser. The power emitted is $2 \times 1 0^{- 3} W$ . The number of photons emitted, on the average, by the source per second is:NEET 2007

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Answer:

Solution:

$η = \frac{p}{m v} = \frac{2 \times 1 0 ^{- 3}}{6.62 \times 1 0 ^{- 34} \times 6 \times 1 0 ^{14}}$ $= 5 \times 1 0^{15}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2007

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