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PhysicsModern PhysicsRadioactivityMedium2 minPYQ_2006

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In a radioactive material the activity at time $t_{1}$ is $R_{1}$ and at a later time $t_{2}$ , it is $R_{2}$ . If the decay constant of the material is $λ$ , then:NEET 2006

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Solution:

$R_{1} = R_{0} e^{- λ_{4}}$ and $R_{2} = R_{0} e^{- λ λ_{2}}$ $\Rightarrow \frac{R _{1}}{R ,} \Rightarrow R_{1} = \frac{e ^{- λ λ_{1}}}{e ^{- λ λ_{2}}} = e^{- λ (t_{1} - t_{2})} = R_{2} e^{- λ (t_{1} - t_{2})}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Radioactivity

⏱ 2mℹ️ Source: PYQ_2006

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