The photosensitive metallic surface has work function h v 0 fall on this surface, the electrons come out with a maximum velocity of 4 × 1 0 6 m / s . When the photon energy is increased 5 h v 0 .

Question

The photosensitive metallic surface has work function h v 0 ​ fall on this surface, the electrons come out with a maximum velocity of 4 × 1 0 6 m / s . When the photon energy is increased 5 h v 0 ​ . Then maximum velocity of photoelectrons will be:NEET 2005

TestHub · Accepted Answer

According to the question 2 h v 0 ​ = h v 0 ​ + 2 1 ​ m ( 4 × 1 0 6 ) 2 5 h v 0 ​ = h v 0 ​ + 2 1 ​ m v 2 ⇒ 4 × 2 1 ​ m ( 4 × 1 0 6 ) ⇒ 2 1 ​ m v 2 v = 8 × 1 0 6 m / s ​

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