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PhysicsModern PhysicsNuclear physicsMedium2 minPYQ_2005

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If radius of $_{13}^{27} Al$ nucleus is estimated to be $3.6$ Fermi then the radius $_{52}^{125} Te$ nucleus be nearly

Answer:

Solution:

$\frac{R}{3.6} = (\frac{125}{27})^{\frac{1}{3}} \Rightarrow R = 6$ fermi

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2005

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