Physics - Modern Physics Question with Solution | TestHub

${}_8{\mathrm{O}}^{16}+{}_1{\mathrm{H}}^1⟶{}_2{\mathrm{X}}^4+{}_2{\mathrm{He}}^4$ Use conservation of charge and mass The conservation of mass number gives $$16+2=A+4\Rightarrow A=14$$ The conservation of atomic number gives. $$8+1=2+2\Rightarrow 2=7$$ Therefore, ${}_2{\mathrm{X}}^4$ is ${}_7{\mathrm{N}}^{14}$