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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB

PhysicsMediumsingle choice

A current of $1.5 A$ is flowing through a triangle, of side $9 cm$ each. The magnetic field at the centroid of the triangle is :
(Assume that the current is flowing in the clockwise direction.)

Options:

Answer:

Solution:

$B_{1} = \frac{μ_{0} I}{4 π R} (2 \sin 60) = \frac{4 π \times 10^{- 7} \times 1.5}{4 π . (\frac{3 \sqrt{3}}{2}) \times 10^{- 2}} \times 2 \times \frac{\sqrt{3}}{2} = 1 \times 10^{- 5}$
$B_{n e t} = 3 B_{1} = 3 \times 10^{- 5} T \otimes$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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