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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentMedium2 minQB

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The dipole moment of a circular loop carrying a currentI, is m and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is:

Options:

Answer:

Solution:

$m =$ magnetic dipole moment $= I A$ . For $L o o p_{1}$ , $m = I π r^{2}$ , $B_{1} = \frac{μ_{0} i}{2 r}$
For $L o o p_{2}$ . If current is constant m is doubled. $r^{1} = \sqrt{2} r$ . $B_{2} = \frac{μ_{0} i}{2 \sqrt{2} r}$ . $\frac{B_{1}}{B_{2}} = \sqrt{2}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: QB

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