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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minQB

PhysicsEasysingle choice

A long straight wire of radius ' $a$ ' caries a steady current $i$ . The current is uniformly distributed across its cross section. The ratio of the magnetic field at $\frac{a}{2}$ and $2 a$ is

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Solution:

$B 2 π \frac{a}{2} = μ_{0} \frac{i}{π a ^{2}} (\frac{π a ^{2}}{4})$ $B_{1} = \frac{μ _{0} i}{4 π a} \dots$ (i) $B_{2} 2 π (2 a) = μ_{0} i$ $B_{2} = \frac{μ _{0} i}{4 π a} \dots (ii)$ $\frac{B _{1}}{B _{2}} = 1$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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