A wire of length L carrying current i is bent into circular loop with (i) one turn (ii) n turns. Find the ratio of magnetic induction at centre in above two cases.

Question

TestHub · Accepted Answer

The same wire length is used in both coils.

$R_{1} = \frac{L}{2 π}, R_{n} = \frac{L}{2 πn}$

$B_{1} = \frac{μ _{0} i}{2 R _{1}} = \frac{μ _{0} πi}{L}$

$B_{n} = \frac{μ _{0} ni}{2 R _{n}} = n^{2} B_{1}$

$B_{1} : B_{n} = 1 : n^{2}$

Answer C.

Physics - Magnetism Question with Solution | TestHub

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