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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic torque & energyMedium2 minQB

PhysicsMediumsingle choice

A small circular loop of conducting wire has radius a and carries current $I .$ It is placed in a uniform magnetic field $B$ perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period $T .$ The mass of the loop is $m$ then:

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Answer:

Solution:

$τ = M B \sin θ = I α$
$π R^{2} i B θ = \frac{m R^{2}}{2} α$
$ω = \sqrt{\frac{2 π i B}{m}} = \frac{2 π}{T}; T = \sqrt{\frac{2 π m}{i B}}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy

⏱ 2mℹ️ Source: QB

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