If magnetic field at axial point 'P' of solenoid shown in figure is X μ 0 n I ( 3 + 1 ) , where turn density 'n' and current through it is I. Find the value of X.

For a finite solenoid, the field at the axial point P is given below. B P = 2 μ 0 n I ( cos θ 1 − cos θ 2 ) cos θ 1 = 2 3 , cos θ 2 = − 2 1 B P = 2 μ 0 n I × 2 3 + 1 = 4 μ 0 n I ( 3 + 1 ) X = 4

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB

PhysicsMediuminteger

If magnetic field at axial point 'P' of solenoid shown in figure is $\frac{μ _{0} n I ( 3 + 1 )}{X}$ , where turn density 'n' and current through it is I. Find the value of X.

Answer:

Solution:

For a finite solenoid, the field at the axial point P is given below.

$B_{P} = \frac{μ _{0} n I}{2} (cos θ_{1} - cos θ_{2})$

$cos θ_{1} = \frac{3}{2}, cos θ_{2} = - \frac{1}{2}$

$B_{P} = \frac{μ _{0} n I}{2} \times \frac{3 + 1}{2} = \frac{μ _{0} n I ( 3 + 1 )}{4}$

$X = 4$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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