A current of 5A exists in a square loop of side 2 1 m . Then the magnitude of the magnetic field B at the centre of the square loop will be p × 1 0 − 6 T . where, value of p is _____ . [ Take μ 0

Question

A current of 5A exists in a square loop of side 2 ​ 1 ​ m . Then the magnitude of the magnetic field B at the centre of the square loop will be p × 1 0 − 6 T . where, value of p is _____ . [ Take μ 0 ​ = 4 π × 1 0 − 7 TmA − 1 ] .

TestHub · Accepted Answer

Let B be the magnetic field due to single side $then B = \frac{μ _{0} i}{4 π d} (sin θ_{1} + sin θ_{2}) = \frac{1 0 ^{- 7} \times 5 \times 2}{\frac{1}{2 2}} \times \frac{1}{2} = 2 \times 1 0^{- 6} ∴ B_{net} at centre O = 4 B = 8 \times 1 0^{- 6}$

Physics - Magnetism Question with Solution | TestHub

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