In a moving coil galvanometer, two moving coils M 1 and M 2 have the following particulars : R 1 = 5Ω , N 1 = 15 , A 1 = 3.6 × 1 0 − 3 m 2 , B 1 = 0.25 T R 2 = 7Ω , N 2 = 21 , A 2

Question

In a moving coil galvanometer, two moving coils $M_{1}$ and $M_{2}$ have the following particulars :
$R_{1} = 5Ω, N_{1} = 15, A_{1} = 3.6 \times 1 0^{- 3} m^{2}, B_{1} = 0.25 T R_{2} = 7Ω, N_{2} = 21, A_{2} = 1.8 \times 1 0^{- 3} m^{2}, B_{2} = 0.50 T$
Assuming that torsional constant of the springs are same for both coils, what will be the ratio of voltage sensitivity of $M_{1}$ and $M_{2}$ ?

TestHub · Accepted Answer

​ Voltage sensitivity = V θ ​ = c R N A B ​ Ratio == ( N 2 ​ A 2 ​ B 2 ​ N 1 ​ A 1 ​ B 1 ​ ​ ) R 1 ​ R 2 ​ ​ = 21 × 1.8 × 0.5 15 × 3.6 × 0.25 ​ × 5 7 ​ = 1 1 ​ ​

Physics - Magnetism Question with Solution | TestHub

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