Physics - Magnetism Question with Solution | TestHub

The magnetic intensity $H$ inside the solenoid is given by:

$H=nI$

Substituting the given values, $n=400{\text{ m}}^{-1}$ and $I=0.5\text{ A}$:

$H=400\times 0.5=200{\text{ A m}}^{-1}$

The magnetic susceptibility $\chi$ is related to the relative permeability ${\mu }_r$ by:

$\chi ={\mu }_r-1$

Given ${\mu }_r=400$, we have:

$\chi =400-1=399$

The magnetization $M$ of the core material is:

$M=\chi H$

$M=399\times 200=79800{\text{ A m}}^{-1}$

This value is approximately $80000{\text{ A m}}^{-1}$, which can be written as $8\times 10^4{\text{ A m}}^{-1}$.

Answer: $8\times 10^4$