The magnetic moment of a bar magnet is 0.5 Am 2 . It is suspended in a uniform magnetic field of 8 × 1 0 − 2 T . The work done in rotating it from its most stable to most unstable position is:

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At stable equilibrium U = − mB cos 0 ∘ = − mB At unstable equilibrium ​ U = − mB cos 18 0 ∘ = + mB W = Δ U W.D. = 2 mB = 2 ( 0.5 ) 8 × 1 0 − 2 = 8 × 1 0 − 2 J ​

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