Two parallel wires of equal lengths are separated by a distance of 3 m from each other. The currents flowing through 1 st and 2 nd wire is 3 A and 4.5 A respectively in opposite directions. The result

Question

Two parallel wires of equal lengths are separated by a distance of 3 m from each other. The currents flowing through 1 st and 2 nd wire is 3 A and 4.5 A respectively in opposite directions. The resultant magnetic field at mid point between the wires ( μ 0 ​ = permeability of free space)

TestHub · Accepted Answer

Using Biot Savart law, B = 2 π r μ 0 ​ I ​ ∴ Magnetic field due to first wire: B 1 ​ = 2 π r μ 0 ​ I 1 ​ ​ = 2 π × 1.5 μ 0 ​ × 3 ​ = 2 π 2 μ 0 ​ ​ ∴ Magnetic field due to second wire: B 2 ​ = 2 π r μ o ​ I 2 ​ ​ = 2 π × 1.5 μ o ​ × 4.5 ​ = 2 π 3 μ 0 ​ ​ ∴ Net field, B = B 1 ​ + B 2 ​ = 2 π 2 μ 0 ​ ​ + 2 π 3 μ 0 ​ ​ = 2 π 5 μ 0 ​ ​

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