An electron in a hydrogen atom revolves around its nucleus with a speed of 6 . 76 × 10 6 m s – 1 in an orbit of radius 0 . 52 Å . The magnetic field produced at the nucleus of the hydrogen atom is ___

Question

An electron in a hydrogen atom revolves around its nucleus with a speed of 6 . 76 × 10 6 m s – 1 in an orbit of radius 0 . 52 Å . The magnetic field produced at the nucleus of the hydrogen atom is _______ T .

TestHub · Accepted Answer

The magnetic field due to the electron is given by
$B = \frac{μ_{0} q v \sin 90 °}{4 π r^{2}}$
The given data is
$v = 6.76 \times 10^{6} m s^{- 1} r = 0.52 \times 10^{- 10} m$
Thus, the magnetic field is
$B = \frac{10^{- 7} \times (1.6 \times \times 10^{- 19}) \times (6.76 \times 10^{6})}{0.52 \times 0.52 \times 10^{- 20}} = 40 T$

Physics - Magnetism Question with Solution | TestHub

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