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PhysicsMagnetismBiot-savart's & Ampere's Circuital lawHard2 minPYQ_2023

PhysicsHardsingle choice

A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube $2 m$ long and $0.2 m$ in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:

Options:

Answer:

Solution:

Given that number of turns, $n = 1200$
Current, $I = 2 A$
Magnetic field at centre inside the solenoid is given by,
$B = μ_{0} nI$
So magnetic intensity at centre of the solenoid,
$H = \frac{B}{μ _{0}} = nI = (\frac{1200}{2}) (2) (∵ B = μ_{0} H) H = 1.2 \times 1 0^{3} Am^{- 1}$

Stream:BITSATSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2023

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