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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minPYQ_2023

PhysicsMediumsingle choice

The magnetic field at a point $P$ situated at perpendicular distance ' $R$ ' from a long straight wire carrying a current of $12 A$ is $3 \times 1 0^{- 5} Wb / m^{2}$ . The value of ' $R$ ' in $mm$ is $[μ_{0} = 4 π \times 1 0^{- 7} Wb / Am]$

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Answer:

Solution:

Using Biot-Savart's Law, $B ∴ R = \frac{μ _{0} I}{2 π R} = \frac{μ _{0} I}{2 π B} = \frac{4 π \times 1 0 ^{- 7} \times 12}{2 π \times 3 \times 1 0 ^{- 5}} = 8 \times 1 0^{- 2} m = 80 mm$

Stream:MHT_CETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2023

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