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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minPYQ_2023

PhysicsMediumsingle choice

An electron makes a full rotation in a circle of radius $0.8 m$ in one second. The magnetic field at the centre of the circle is $(μ_{0} = 4 π \times 1 0^{- 7} SI units)$

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Answer:

Solution:

$ω = \frac{2 π}{T} I = \frac{q ω}{2 π} = \frac{1.6 \times 1 0 ^{- 19} \times 2 π}{2 π} \dots . (∵ I = \frac{q}{t}) I = 1.6 \times 1 0^{- 19} A$ $∴$ The magnetic field at the centre of the circle is: $B = \frac{μ _{0} I}{2 r} = \frac{4 π \times 1 0 ^{- 7} \times 1.6 \times 1 0 ^{- 19}}{2 \times 0.8} B = 4 π \times 1 0^{- 26} T$

Stream:MHT_CETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2023

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