Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2022

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An electric current $I$ enters and leaves a uniform circular wire of radius $r$ through diametrically opposite points. A charged particle $q$ moves along the axis of circular wire passes through its centre at speed $v$ . The magnetic force on the particle when it passes through the centre has a magnitude.

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Solution:

Force on a moving charged particle in uniform magnetic field $F = Bq v sin θ$ Since, charge particle moves along the axis of circular current carrying loop, therefore, $θ = 0^{\circ}$ or $18 0^{\circ}$ When $θ = 0^{\circ}; F = Bq v sin 0^{\circ}$ $F = 0$ When $θ = 18 0^{\circ}, F = Bq u sin 18 0^{\circ}$ $F = 0$

Stream:BITSATSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2022

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