A magnet makes 40 oscillations per minute at a place having magnetic field induction of 0.1 × 10 – 5 T . At another place, it takes 2.5 s to complete one vibration. The value of earth's horizontal field at that place is

T = 2 π I M × B H ⇒ T ∝ 1 B H ⇒ T 1 T 2 = ( B H ) 2 ( B H ) 1 ⇒ 60 / 40 2.5 = ( B H ) 2 0.1 × 1 0 - 5 ⇒ ( B H ) 2 = 0.36 × 1 0 - 6 T

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PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

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A magnet makes $40$ oscillations per minute at a place having magnetic field induction of $0.1 \times 10^{- 5} T$ . At another place, it takes $2.5 s$ to complete one vibration. The value of earth's horizontal field at that place is

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Answer:

Solution:

$T = 2 π \sqrt{\frac{I}{M \times B_{H}}} \Rightarrow T \propto \frac{1}{\sqrt{B_{H}}}$

$\Rightarrow \frac{T_{1}}{T_{2}} = \sqrt{\frac{(B_{H})_{2}}{(B_{H})_{1}}} \Rightarrow \frac{60 / 40}{2.5} = \sqrt{\frac{(B_{H})_{2}}{0.1 \times 1 0^{- 5}}}$

$\Rightarrow (B_{H})_{2} = 0.36 \times 1 0^{- 6} T$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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