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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

PhysicsEasysingle choice

With a standard rectangular bar magnet, the time period of a vibration magnetometer is $4 s$ . The bar magnet is cut parallel to its length into four equal pieces. The time period of vibration magnetometer when one piece is used (in second) (bar magnet breadth is small) is

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Answer:

Solution:

The time period of the magnet, $T = 2 π \sqrt{\frac{I}{MB}}$

When the magnet is cut parallel to its length into four equal pieces.

Then new Magnetic moment, $M^{'} = \frac{M}{4}$

New moment of inertia, $I^{'} = \frac{I}{4}$

$∴$ New time period $T = 2 π \sqrt{\frac{I}{MB}}$

$\Rightarrow T = T^{'} = 4 s$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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