Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

Find the magnitude of the magnetic field at the center of an equilateral triangular loop of side length $1 m$ which is carrying a current of $10 A$ . (Take $μ_{0} = 4 π \times 10^{- 7} {NA}^{- 2}$ )

Options:

Answer:

Solution:

Magnetic field due to wire $BC$ is $\Rightarrow B = \frac{μ_{0}}{4 π} \frac{i}{ℓ} \times 2 \sqrt{3} [\frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2}] \otimes$

Net magnetic field at centre $= 3 B$

$= \frac{μ_{0}}{4 π} \frac{i}{ℓ} \times 2 \sqrt{3} [\frac{\sqrt{3}}{2} + \frac{\sqrt{3}}{2}] 3 \otimes$

$= \frac{μ_{0}}{4 π} \frac{1}{ℓ} 6 (1) 3 = 10^{- 7} \times \frac{10}{1} \times 18 = 18 \times 10^{- 6} T$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...