Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentHard2 minPYQ_2020

PhysicsHardnumerical

A non-conducting rod of lengthLwith linear charge density $λ = λ_{0} x$ wherexis the distance from endAis rotating with constant angular speed $ω$ about the same end. If the angular velocity of the rod ( $ω$ ) is large, then the magnetic dipole moment of the system is $\frac{ω λ_{0} L^{4}}{n}$ . What is the value of $n$ ?

Answer:

8.00

Solution:

$d q = λ_{0} x d x \Rightarrow i = \frac{ω λ_{0} x d x}{2 π}$
$d m = \frac{ω λ_{0} x d x}{2 π} π x^{2} \Rightarrow m = \int d m = \int \frac{ω λ_{0}}{2} x^{3} d x$
$∴ m = \frac{ω λ_{0} L^{4}}{8}$
$n = 8$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...