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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

PhysicsEasysingle choice

A short bar magnet is placed in a uniform magnetic field of $0.25 T$ , with its axis at an angle of $30 °$ with the field. If it experiences a torque of magnitude $4.5 \times 10^{- 2} N m$ , then its magnetic moment is

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Answer:

Solution:

The magnitude of torque acting on a magnetic dipole in a uniform magnetic field is

$τ = M B sinθ = 4.5 \times 10^{- 2} N m M \times 0.25 \times \sin 30 ° = 4.5 \times 10^{- 2} N m \Rightarrow M = 0.36 N m T^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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